50x^2+5x-120=0

Solution for 50x^2+5x-120=0 equation:

50x^2+5x-120=0

a = 50; b = 5; c = -120;
Δ = b2-4ac
Δ = 52-4·50·(-120)
Δ = 24025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24025}=155$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-155}{2*50}=\frac{-160}{100}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+155}{2*50}=\frac{150}{100}
=1+1/2
$